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(5x^(2)-4)^((1)/(4))=x
We move all terms to the left:
(5x^(2)-4)^((1)/(4))-(x)=0
We add all the numbers together, and all the variables
(5x^2-4)^(+1/4)-x=0
We add all the numbers together, and all the variables
-1x+(5x^2-4)^(+1/4)=0
We multiply all the terms by the denominator
-1x*4)+(5x^2+1-4)^(=0
We add all the numbers together, and all the variables
-1x*4)+(5x^2=0
Wy multiply elements
-4x^2=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-8}=0$
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